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(C)=30C-0.005C^2
We move all terms to the left:
(C)-(30C-0.005C^2)=0
We get rid of parentheses
0.005C^2-30C+C=0
We add all the numbers together, and all the variables
0.005C^2-29C=0
a = 0.005; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·0.005·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*0.005}=\frac{0}{0.01} =0 $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*0.005}=\frac{58}{0.01} =5800 $
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